Question

Reena is 6 years older than her brother Ajay if the sum of their ages is 28 years what are the present ages

Answer 1

Let the age of Ajay be a

Age of Reena = a +6

a + a + 6 = 28

=> 2a = 22

=> a = 11

Ajay's age = 11 years

Reena's age = 17 years

Answer 2

$\huge{\bf{\underline{\fbox{\pink{Question:}}}}}$

Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, what are the present ages?

$\huge{\rm{\underline{\fbox{\blue{Answer:}}}}}$

Let the age of Ajay be x

And the age of Reena is x + 6

ATQ,

$\quad \quad x + x + 6 = 28$

$\implies 2x + 6 = 28$

$\implies 2x = 28 - 6$

$\implies 2x = 22$

$\implies x = \cancel{ \dfrac{22}{2} }$

$\implies x = 11$

Hence, present age of Ajay = $\green{\textbf{\textsf{\underline{11}}}}$

and present age of Reena => 11 + 6 = $\orange{\textbf{\textsf{\underline{17}}}}$