Question

solve the following system of equations: 1) 2x + y = 7
4x - 3y + 1 = 0​

Answer 1

Answer:

$2x + y = 7 \\ y = 7 - 2x \\ putting \: the \: value \: of \: y \: in \: second \: equation \: we \: get \\ \\ 4x$

$2x + y = 7 \\ y = 7 - 2x \\ putting \: ) \: value \: of \: y \: in \: second \: equation \: we \: get \\ \\ 4x - 3(7 - 2x) + 1 = 0 \\ 4x + 21 - 6x + 1 = 0 \\ - 2x = - 22 \\ x = 11 \\ putting \: the \: valw \\ ue \: of \: x \: in \: any \: eq \: we \: get \\ 2 \times 11 + y = 7 \\ y = - 17$

I think you are also in class 10

Answer 2

SUBSTITUTION METHOD:

2x + y = 7 ————— equation no.1

4x - 3y + 1 = 0 can be written as,

4x - 3y = -1 ————— equation no.2

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Take value of x in terms of y or vice versa,

2x + y = 7

2x = 7 - y

x = (7 - y)/2

Put the value of x in equation no.2.

4x - 3y = -1

4(7 - y)/2 - 3y = -1

2(7 - y) - 3y = -1

14 - 2y - 3y = -1

14 - 5y = -1

-5y = -1-14

-5y = -15

5y = 15

y = 15/5

y = 3

Put value of y in any of the two equations,

2x + y = 7

2x + 3 = 7

2x = 7 - 3

2x = 4

x = 4/2

x = 2

VERIFICATION:

Put value of x and y in any of the two equations,

2x + y = 7

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Hence, Verified

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