Question

Solve the following system of equations by substitution method: x/2 + y = 0.8, x + y/2 = 7/10

Answer 1

Answer:

$\large\boxed{\sf{x=0.4,\;\;y= 0.6}}$

Step-by-step explanation:

Given a pair of linear equations such that,

x/2 + y = 0.8 .......(1)

x + y/2 = 0.7 ........(2)

Now, we have to find the values of x and y by substitution method.

For this, lets find the value of x in terms of y.

Solving eqn (2), we get,

=> x = 0.7 - y/2

Now, substituting the value of x in eqn (1),

We will get,

=> (0.7 - y/2)/2 + y = 0.8

=> 0.7/2 - y/4 + y = 0.8

=> 3y/4 = 0.8 - 0.7/2

=> 3y/4 = (1.6-0.7)/2

=> 3y/4 = 0.9/2

=> y = (0.9 × 4)/(2 × 3)

=> y = 0.6

Now, putting this value to find x, we get,

=> x = 0.7 - 0.6/2

=> x = 0.7 - 0.3

=> x = 0.4

Hence, x = 0.4 and y = 0.6