Question

Solve the following pair of linear equations by substitution method:
0.5x + 0.8y = 3.4
0.6x — 0.3y = 0.3

Answer 1

Answer:

$\large\boxed{\sf{x=\dfrac{37}{16},\;y=\dfrac{58}{16}}}$

Step-by-step explanation:

Given a pair of linear equations such that,

0.5x + 0.8y = 3.4 ..........(1)

0.6x - 0.3y = 0.3 ...........(2)

Now, we have to find the values of x and y by substitution method.

For this, let's find value of y in terms of x.

Solving eqn (2), we get,

=> 0.3(2x -y ) = 0.3

=> 2x - y = 1

=> y = 2x - 1

Now, substitute this value in eqn (1),

Therefore, we will get,

=> 0.5 + 0.8(2x -1) = 3.4

=> 1.6x - 0.8 = 3.4 - 0.5

=> 1.6x = 2.9 + 0.8

=> 1.6x = 3.7

=> x = 3.7/1.6

=> x = 37/16

Now, putting this value, we get,

=> y = (2 × 3.7)/1.6 - 1

=> y = 7.4/1.6 - 1

=> y = (7.4 - 1.6)/1.6

=> y = 5.8/1.6

=> y = 58/16

Hence, x = 37/16 and y = 58/16