Question

solve the following system of equations by substitution method:
5x+2y=8 , 3x-5y=11​

Answer 1

Answer:

3x-5y=11---(i)

take 5x on the right side so 2y=8-5x---(ii)

then take 2 on the right side -->y=(8-5x)/2---(iii)

Thus , substituting (iii) in (i),

3x-5((8-5x)/2)=11

∴3x-(40-25x)/2=11

∴(6x-40+25x)/2=11

∴31x-40=22

∴31x=62

∴x=2

Step-by-step explanation:

Answer 2

here is your answer

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