Question

Solve the following system of equations by the method of substitution:
2x-3y - 1 = 0

X+(3x-2y)/X-(3x+2y)=-3
​

Answer 1

Answer:

x=2,y=1

Step-by-step explanation:

2x-3y-1=0

0+1=2x-3y

2x-3y=1

if 2x-3y=1

then 2x=4,3y=3

so 4-3=1

2x=4,3y=3

x=2,y=1