Math, asked by aishusrini5086, 11 months ago

Solve the following system of linear equations graphically and shade the region between the two lines and x-axis:
(i) 2x + 3y = 12
x – y = 1
(ii) 3x + 2y – 4= 0
2x – 3y – 7 = 0
(iii) 3x + 2y – 11 = 0
2x – 3y + 10 = 0

Answers

Answered by nikitasingh79
7

Given:  System  of linear equations:  

(i) 2x + 3y = 12  

y = (12 - 2x)/3…………(1)

x – y = 1

y = x - 1 ……….(2)

 

Solution :

For eq 1 :  

When x = 0,then y = 4

When x = 6 , then y = 0

When x = 3 , then y = 2

2x + 3y = 12  passes through (0, 4) and (6, 0) , (3,2).

Plot these points on a graph paper.

 

For eq 2 :  

When x = 0 ,then y = - 1

When x = 1 , then y = 0

When x = 3 , then y = 2

x – y = 1 passes through (0, -1) , (1, 0), (3,2).

Plot these points on a graph paper.

Two lines intersect at a point C (3,2) .

Hence x is 3 and y is 2.

(ii) 3x + 2y – 4= 0

y = (4 - 3x)/2 …………(1)

2x – 3y – 7 = 0

y = (2x - 7)/3 ……..(2)

For eq 1 :  

When x = 0,then y = 2

When x = 2 , then y = - 1

When x = - 2 , then y = 5

3x + 2y – 4= 0 passes through (0,2) and (2, -1), (-2,5)

Plot these points on a graph paper.

For eq 2 :  

When x = 2,then y = - 1

When x = -1 , then y = -3

When x = 5 , then y = 1

2x – 3y – 7 = 0  passes through (2, -1) , (- 1,3), (5,1).

Plot these points on a graph paper.

Two lines intersect at a point B (2,- 1) .

Hence x is 2 and y is - 1.

HOPE THIS ANSWER WILL HELP YOU……

 

Some more questions :  

Solve the following system of equations graphically:

Shade the region between the lines and the y-axis

(i) 3x – 4y = 7

5x + 2y = 3

(ii) 4x – y = 4

3x + 2y = 14

https://brainly.in/question/15918433

 

Solve the following systems of equations graphically:

x+y=4

2x-3y=3

https://brainly.in/question/15918174

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Answered by poonanjagay1985
6

Answer:

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