Question

Solve the following system of linear equations.
x + y + 2z = 8
–x –2y + 3z = 1
3x – 7y + 4z = 10

Answer 1

$x = 1 \\ y = 2$
z=5

Answer 2

x+y+2z=8

-x-2y+ 3z= 1

x+y+2z - x- 2 y+3z= 8+1= 9

- y+ 5z= 9

(-X - 2 y+ 3z)x3=3

- 3 X - 6 y+9 z = 3

3 X-7y+ 4z = 10

-13 y+13z =13

13x(-y+z)=13

-y+z=1

-y+5z=9

4z=9-l=8

z=8/4

= 2 Z=2

-y+z=1

-y+2=1

-y=l-2=-1

y =1 y=1

X +y+2z=8

X +1+2x2=8

X+1+4= 8

X +5=8

X=8-5

=3 X=3

x=3, y=1, z=2