Question

solve the following system of linear inequalities 2x+3/4>3, x-4/-3<2​

Answer 1

Answer:

x>9/2

x<-2

Step-by-step explanation:

$\frac{2x + 3}{4} > 3$

multiply by 4

$= \frac{2x + 3}{4} \times 4 > 3 \times 4$

$= \: 2x + 3 > 12$

$= \: 2x > 12 - 3$

$= 2x > 9$

$=x > \frac{9}{2}$

2nd

$\frac{x - 4}{ - 3} < 2$

multiply by (-3)

$= \frac{x - 4}{ - 3} \times ( - 3) < 2 \times ( - 3)$

$= x - 4 < - 6$

$= x < - 6 + 4$

$= x < - 2$