Solve the following systems of equations:
2(3u - v) = 5uv
2(u + 3v) = 5uv
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u = 2 ; v = 1
Step-by-step explanation:
Let 1/u = x and 1/v = y
2(3u - v) = 5uv
6u - 2v = 5uv
Dividing by uv, we get: 6/v - 2/u = 5
-2x +6y = 5-------(1)
2(u + 3v) = 5uv
2u + 6v = 5uv
Dividing by uv, we get: 2/v + 6/u = 5
6x + 2y = 5 ------------(2)
Adding (1)*3 & 2, we get: 20y = 20
Therefore y = 1
Substituting y in (1), we get: -2x + 6 = 5
Therefore x = 1/2
So x = 1/u = 1/2. Therefore u = 2
So y = 1/v = 1. Therefore v = 1
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