Solve the following systems of equations:
3/(x + y) + 2/(x – y) = 2
9/(x + y) – 4/(x – y) = 1
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Solve the following systems of equations:
3/(x + y) + 2/(x – y) = 2
9/(x + y) – 4/(x – y) = 1
The values of x and y are:
x = 5/2
y = 1/2
Given,
3/(x + y) + 2/(x – y) = 2
9/(x + y) – 4/(x – y) = 1
Let 1/(x+y) = u and 1/(x-y) = v
Therefore, we have,
3u + 2v = 2 ..........(1)
9u – 4v = 1 ...........(2)
solving the above 2 equations (1) and (2), we get,
u = 1/3
v = 1/2
Now, we have,
1/(x+y) = 1/3
⇒ x+y = 3 .........(3)
1/(x-y) = 1/2
⇒ x-y = 2 ..........(4)
solving the above 2 equations (3) and (4), we get,
x = 5/2
y = 1/2
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