Question

Solve the following systems of equations:
2x – (3/y) = 9
3x + (7/y) = 2 ,y ≠ 0

Answer 1

Given:

2x - (3/y) =9

3x + (7/y) = 2.

To find:

Solution of the equations

Answer:

• These equations can be written as
• 2xy-9y = 3
• 3xy-2y= -7
• Multiplying 1st equation with the coefficient of 2nd equation and 2nd equation with coefficient of 1st equation,we get
• 6xy-27y = 9
• 6xy-4y = -14
• By solving these equations, we get y=-5/23
• And x= -12/5.

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

2x - 3/y = 9 …………...(a)

3x + 7/y = 2…………...(b)

Now,

Multiply (a) by 3 & (b) by 2 we get,

6x - 9/y = 27 ………..(c)

6x + 14/y = 4 ………..(d)

Now,

Subtract (c) from (d) we get,

23/y = -23

y = -23/23

y = -1

Now,

Substituting value of y in (d),

6x - 9/y = 27

6x - 9/-1 = 27

6x + 9 = 27

6x = 27 - 9

6x = 18

x = 18/6

x = 3

Therefore,

x = 3 & y = -1