Solve the following systems of equations:
3x – (y + 7)/11 + 2 = 10
2y + (x + 11)/7 = 10
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x = 3 and y = 4.
Step-by-step explanation:
3x – (y + 7)/11 + 2 = 10
3x (11) – (y + 7) +2(11) = 10(11)
33x - y - 7 +22 = 110
33x - y = 95-------------(1)
2y + (x + 11)/7 = 10
2y(7) + (x + 11) = 10 (7)
14y + x = 70 - 11
x + 14y = 59-------------(2)
Adding equations (1)*14 & 2, we get: 463x = 1389. So x = 1389/463 = 3
Substituting x = 3 in equation 2, we get: 3 + 14y = 59
y = 56/14 = 4
Hence solved. x = 3 and y = 4.
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