Solve the following systems of equations:
Answers
Given pair of system of equation :
1/2x + 1/3y = 2 …………...( 1 )
1/3x + 1/2y = 13/6 …………...( 2 )
Let 1/x = u & 1/y = v
Now eq 1 becomes :
u/2 + v/3 = 2
(3u + 2v)/6 = 2
3u + 2v = 2 × 6
3u + 2v = 12 …………..(3)
Eq 2 becomes :
u/3 + v/2 = 13/6
(2u + 3v)/6 = 13/6
2u + 3v = 13/6 × 6
2u + 3v = 13 …………..(3)
Elimination method is used to solve this Linear pair of Equations:
On multiplying eq 1 by 2 and eq 2 by 3 :
6u + 4v = 24 …………..(4)
6u + 9v = 39………..(5)
On subtracting equation (5) from (4) :
6u + 4v = 24
6u + 9v = 39
(-) (-) (-)
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- 5 v = - 15
v = 15/5
v = 3
On putting v = 3 in eq (3) we get :
3u + 2v = 12
3u + 2 × 3 = 12
3u + 6 = 12
3u = 12 - 6
3u = 6
u = 6/3
u = 2
Therefore , 1/x = u = 2 & 1/y = v = 3
Then , x = ½ & y = ⅓
Hence, the value of the given system of equation is x = ½ and y = 1/3.
Hope this answer will help you…
Some more similar questions from this chapter :
Solve the following systems of equations:
1/7x + 1/6y = 3
1/2x - 1/3y = 5
brainly.in/question/17131588
Solve the following systems of equations:
x + y/2 = 4
x/3 + 2y = 5
brainly.in/question/17132545
Answer:
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