Question

Solve the following systems of equations :
x – y + z = 4
x – 2y + 3z = 9
2x + y + 3z = 1

Answer 1

Answer:

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Answer 2

x = 7 ;  y = -1; z = -4

Step-by-step explanation:

 x – y + z = 4  --------------(1)

 x – 2y + 3z = 9 --------------(2)

2x + y + 3z = 1 --------------(3)

Adding 1 & 3, we get: 3x + 4z = 5 --------------(4)

Adding 2 & (3)*2, we get: 5x + 6z = 11 --------------(5)

(4)*5 = 15x + 20z = 25

(5)*3 = 15x + 18z = 33

Subtracting, we get: 2z = -8.

Therefore z = -4

Substituting z in (4), we get 3x -16 = 5

Therefore x = 7

Substituting x and z in (1), we get 7 -y -4 = 4

Therefore y = -1