Math, asked by eshwarchandra6190, 11 months ago

Solve the following systems of equations :
4/x + 3y = 14
3/x – 4y = 23

Answers

Answered by 5k2j
0

Answer:

what class question is about

Answered by topwriters
2

x = 1/5, y = -2

Step-by-step explanation:

Given linear equations are:

4/x + 3y = 14

3/x – 4y = 23

Let 1/x = u and y = v, we get:

4u + 3v = 14-------------(1)

3u - 4v = 23-------------(2)

(1)*3 will be 12u + 9v  = 42

(2)*4 will be 12u - 16v = 92

Subtracting (2) from (1), we get: 25v = -50

Therefore v = -2

Substituting in v = -2 equation 2, we get 3u +8 = 23

u = 15/3 = 5

1/x = 5, so x = 1/5

v = -2 = y

Therefore y = -2.

Hence solved. x = 1/5, y = -2

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