Solve the following systems of equations :
4/x + 3y = 14
3/x – 4y = 23
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what class question is about
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x = 1/5, y = -2
Step-by-step explanation:
Given linear equations are:
4/x + 3y = 14
3/x – 4y = 23
Let 1/x = u and y = v, we get:
4u + 3v = 14-------------(1)
3u - 4v = 23-------------(2)
(1)*3 will be 12u + 9v = 42
(2)*4 will be 12u - 16v = 92
Subtracting (2) from (1), we get: 25v = -50
Therefore v = -2
Substituting in v = -2 equation 2, we get 3u +8 = 23
u = 15/3 = 5
1/x = 5, so x = 1/5
v = -2 = y
Therefore y = -2.
Hence solved. x = 1/5, y = -2
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