solve the following systems of graphing 1) 2x + y =5 and x- 3y=-8 2) 6x-3y =-9 and 2x + 2y=-6
Answers
Answer:
1) x = 1, y = 3
2) x = -2, y = -1
Step-by-step explanation:
1) Given that
2x + y = 5
=> 6x + 3y = 15 . . . . . . . . . . . . . . . (i) [multiplying both sides by 3]
Also, given that,
x - 3y = -8 . . . . . . . . . . . . . . . . . . . (ii)
Adding equation (i) and (ii):
7x = 7
∴ x = 1
Putting the value of x into equation (ii):
6 + 3y = 15
=> 3y = 15 - 6 = 9
∴ y = 3.
2) Given that,
6x - 3y = -9
=> 2x - y = -3 . . . . . . . . . . . . . . . . (i) [dividing both sides by 3]
Also given that,
2x + 2y = -6
=> x + y = -3 . . . . . . . . . . . . . . . . . (ii) [dividing both sides by 2]
Adding equation (i) and (ii):
3x = -6
∴ x = -2,
Putting the value of x into equation (ii):
-2 + y = -3
∴ y = -3 + 2 = -1
Given : Pair of Linear Equation
1) 2x + y =5 and x- 3y=-8
2) 6x-3y =-9 and 2x + 2y=-6
To Find : Solve for x and y
Solution:
1) 2x + y =5 and x- 3y=-8
Draw line 2x + y = 5
x = 0 => y = 5
x = 1 => y = 3
x = 2 => y = 1
Plot these points and draw a straight line passing through the points
x - 3y = - 8
x = 1 => y = 3
x = -2 => y = 2
Plot points and draw a straight line
Lines intersects at x = 1 and y = 3
Solution is (1 , 3)
Use same procedure :
2) 6x-3y =-9 and 2x + 2y=-6
x = -2 , and y = - 1 is the required solution
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