Solve the following systems of linear equations by using the elimination method equating the coefficients:
3x+2y=11
2x+3y=4
Answers
Answered by
7
3x+2y=11------------(1)
2x+3y=4--------------(2)
multipling EQ1 BY 2 AND EQ2 BY 3
6x+4y=22
6x+9y=12
(*substracting)
------------------------------------
-5y=10
-y=2⇒y=-2
therefore x=5
2x+3y=4--------------(2)
multipling EQ1 BY 2 AND EQ2 BY 3
6x+4y=22
6x+9y=12
(*substracting)
------------------------------------
-5y=10
-y=2⇒y=-2
therefore x=5
ojaswi7:
It's subtracting, not substracting
IT'S MATH CHILL
Similar questions