Question

solve the following
$7 \frac{1}{7} \div3 \frac{4}{7} + (1 \frac{1}{2} - 1 \frac{1}{4} ) \times (1 \frac{1}{3} + 1 \frac{3}{9} )$

Answer 1

Answer:

Step-by-step explanation:

Resent solve you

Answer 2

HELLO DEAR,

GIVEN:- $\bold{\mathsf{7 \frac{1}{7} \div3 \frac{4}{7} + (1 \frac{1}{2} - 1 \frac{1}{4} ) \times (1 \frac{1}{3} + 1 \frac{3}{9} )}}$

$\bold{\implies \frac{49 + 1}{7} \div \frac{21 + 4}{7} + (\frac{2 + 1}{2} - \frac{4 + 1}{4}) \times( \frac{3 + 1}{3} + \frac{9 + 3}{9})}$

$\bold{\implies \frac{50}{7}\times \frac{7}{25} + (\frac{6 - 5}{4}) \times (\frac{12 + 12}{9})}$

$\bold{\implies 2 + (\frac{1}{4}) \times (\frac{24}{9})}$

$\bold{\implies 2 + \frac{9 + 96}{36}}$

$\bold{\implies 2 + 105/36}$

$\bold{\implies 2 + 35/12}$

$\bold{\implies \frac{24 + 35}{12}}$

$\bold{\implies \frac{59}{12}}$

$\bold{\implies 4\frac{11}{12}}$

I HOPE IT'S HELP YOU DEAR,
THANKS