Question

Solve the following three parts​

Answer 1

Answer:

$(ii) \frac{( - 7)}{20} + \frac{14}{( - 15)} + \frac{1}{10} \\ = \frac{( - 7)}{20} - \frac{14}{15} + \frac{1}{10} \\ = \frac{( - 21) - 64 + 6}{60} \\ = \frac{ ( - 77)}{60} \\ (ii) \frac{18}{( - 11)} and \frac{( - 6)}{5} \\ = \frac{( - 18)}{11} + \frac{( - 6)}{5} \\ = \frac{( - 18)}{11} - \frac{6}{5} \\ = \frac{( - 90) - 66}{55} \\ = \frac{( - 156)}{55} \\ (iii) \frac{31}{7} and \frac{15}{8} \\ = \frac{31}{7} + \frac{15}{8} \\ = \frac{248 + 105}{56} \\ = \frac{353}{56}$

Answer 2

Answer:

ii)

20

(−7)

+

(−15)

14

+

10

1

=

20

(−7)

−

15

14

+

10

1

=

60

(−21)−64+6

=

60

(−77)

(ii)

(−11)

18

and

5

(−6)

=

11

(−18)

+

5

(−6)

=

11

(−18)

−

5

6

=

55

(−90)−66

=

55

(−156)

(iii)

7

31

and

8

15

=

7

31

+

8

15

=

56

248+105

=

56

353