Question

solve the following word problem
(b) Find the rate of interest when:
(i) Principal = 3000, simple interest = 3360 and time = 3 years
(ii) Principal = 2100. simple interest = 336 and time = 2 years
this is the question of subject maths chapter name commercial math ​

Answer 1

Step-by-step explanation:

p=3000

si=3360

t=3

r=?

si=p*r*t/100

3360=3000*r*3/100

3360=90r

r=3360/90

r=37%

Answer 2

Answer:

$rate \: of \: interest \\ \frac{3360 \times 100}{3000 \times 3} = \frac{112}{3} = 37 \frac{1}{3} \%$

$rate \: of \: interest \\ \frac{336 \times 100}{2100 \times 2} =8\%$

Step-by-step explanation:

Hope it helps.....