2.
Two small spherical metal balls, having equal
masses, are made from materials of densities P
and P2 (P = 8p,) and have radii of 1 mm and 2
mm, respectively, they are made to fall vertically
(from rest) in a viscous medium whose coefficient
of viscosity equals n and whose density is 0.1p.
The ratio of their terminal velocities would be,
[NEET- 2019 (Odisha)]
PINOS
Answers
Answer:
Explanation:
Given Two small spherical metal balls, having equal
masses, are made from materials of densities P
and P2 (P = 8p,) and have radii of 1 mm and 2
mm, respectively, they are made to fall vertically
(from rest) in a viscous medium whose coefficient
of viscosity equals n and whose density is 0.1 p.
The ratio of their terminal velocities would be,
We know that Vt = 2 g r^2 / 9 ƞ (σ – Δ)
Therefore v1 / v2 = (r1/r2)^2 (σ1 – Δ / σ2 – Δ)
= (1/2)^2 (8 σ2 – 0.1σ2 / σ2 – 0.1σ2)
= 1/4 x 7.9 σ2 / σ2
= 7.9 / 3.6
= 79 / 36
Answer:79/36
Explanation:
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KnjroopaAce
Answer:
Explanation:
Given Two small spherical metal balls, having equal
masses, are made from materials of densities P
and P2 (P = 8p,) and have radii of 1 mm and 2
mm, respectively, they are made to fall vertically
(from rest) in a viscous medium whose coefficient
of viscosity equals n and whose density is 0.1 p.
The ratio of their terminal velocities would be,
We know that Vt = 2 g r^2 / 9 ƞ (σ – Δ)
Therefore v1 / v2 = (r1/r2)^2 (σ1 – Δ / σ2 – Δ)
= (1/2)^2 (8 σ2 – 0.1σ2 / σ2 – 0.1σ2)
= 1/4 x 7.9 σ2 / σ2
= 7.9 / 3.6
= 79 / 36