Math, asked by maheshbedre, 1 year ago

solve the formula method

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Answered by ravishukla7
0
3{x^2+1/x^2}-4{x-1/x}-6=0

x^2+1/x^2-2×x×1/x+2×x×1/x

x^2+1/x^2={x-1/x}^2+2

let {x-1/x} = y------(1)

3×{y^2+2}-4y-6=0
3y^2-4y=0

3y^2=4y

3y=4

y=4/3

from eqa(1)

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