Question

The hypotenuse of a right triangle is 17cm long.if one of the remaning two sides is of length 8cm,find the length of another side.

Answer 1

$(h)^{2} = {(p)}^{2} + {(b)}^{2} \\ \\ h = 17 \\ p = 8 \\ \\ ( {17})^{2} = ( {8})^{2} + {(b)}^{2} \\ \\ {(b)}^{2} = {(17)}^{2} - {(8)}^{2} \\ \\ {(b)}^{2} = 289 - 64 = 225 \\ \\ b = \sqrt{225 } \\ \\ b = 15 \\ \\ \\ \\ hence \: the \: another \: side \: is \: 15cm$

Answer 2

According to the phythqgoras theoream
Ac sq 2 = Ab sq2 + BC sq 2
Thus let hyphotenuse be Ac....and other two sides be Ab and BC respectively
Now according to this question
Given that : Ac = 17 cm....and Ab = 8 cm
we need to find BC
Thus substituting these values in phythagoras formula we get
17×17 cm sq= 8×8 cm sq + BC sq
289 cm sq= 64 cm sq + BC sq
289-64 cm sq = BC sq
225 cm sq = BC sq
√225cm = BC
15= BC.
Thus the third side will be 15 cm