ten identical lengths of wire are laid closely side-by-side. their combined width is measured and found to be 14.2mm. calculate:
a. the radius of a single wire.
b. the volume in mm³ of a single wire if its length is 10.0cm.
content quality answer needed!
Answers
Answered by
140
a) The combined width is the sum of the diameters of the ten rods.
The diameter of one rod is thus :
14. 2/10 = 1.42 mm
b) The volume of a single wire.
We first change the length to be in mm as follows.
1 cm = 10mm
10 × 10 = 100 mm
Volume = πr²h
r = 1.42 / 2 = 0.71
Volume = 3.142 × 0.71² × 100 = 158.39
= 158.39 mm³
Answered by
7
Answer:
The resistance of the original single wire of copper =R
1
=
πr
1
2
ρl
, where r
1
=6mm and R
1
=10Ω
The resistance of each new copper wire =R
2
= πr2
2ρρ , where r 2
=2mm
∴ R 1 R 2
=( r2r r1 ) 2
=( 26 ) 2= 19
i.e., R
2 =9R
1 =90Ω
Similar questions