Math, asked by sakinanajmig8, 4 months ago

Solve the given equation:
(5y+2)-(16/3y+1)=8​

Answers

Answered by achyutamseth21
0

Answer:

We shall solve for y.

Step-by-step explanation:

5y+ 2- 16/ 3y- 1= 8

5y^2 + 6y - 16- 3y/ 3y=8

5y^2+ 3y- 16= 8*3y

5y^2- 16= (24- 3)y

5y^2- 16- 21y= 0

Now, factorizing it will give the answer:

5y^2- 21y- 16= 0

5y^2- 5y - 16y- 16=0

-5y(y+1)-16(y+1)

(-5y- 16)(y+1)

Hope this helps you.

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