solve the given equation by the method of completing the squares: x^2+12x-45=0
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x^2+12x-45=0
So by method of completing square,
we have the form of (x+a)2=x^2+2ax+c
So x^2+2(6)x-45=0
Here tha value of a = 6
So, a^2 = 36
So, adding and subtracting 36,
we get,
x^2+2(6)x+36-36-45=0
⇒(x+6)^2-81=0
⇒(x+6)^2-9^2=0
⇒(x+6)^2=9^2
⇒(x+6) = ±9
⇒x=-6±9
⇒x=3,-15 Ans
So by method of completing square,
we have the form of (x+a)2=x^2+2ax+c
So x^2+2(6)x-45=0
Here tha value of a = 6
So, a^2 = 36
So, adding and subtracting 36,
we get,
x^2+2(6)x+36-36-45=0
⇒(x+6)^2-81=0
⇒(x+6)^2-9^2=0
⇒(x+6)^2=9^2
⇒(x+6) = ±9
⇒x=-6±9
⇒x=3,-15 Ans
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