solve the given pair of equations using substitution method 2x+y=7,4x-3y+1=0
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=>2x+y =7
=>y=7-2x
So,
y=7-2x
=>4x-3y+1=0 ------------eq.1
Substituting y to eq.1. :-
4x-3(7-2x)+1=0
4x-21+6x+1=0
10x-20=0
10x=20
x= 20/10
x=2
y=7-2x
y=7-2(2)
y=7-4
y=3
----------------------
|
|. x = 2
|
|. y =3
|---------------------
I hope you got the answer.
Don't forget to mark me the Brainliest !!
=>y=7-2x
So,
y=7-2x
=>4x-3y+1=0 ------------eq.1
Substituting y to eq.1. :-
4x-3(7-2x)+1=0
4x-21+6x+1=0
10x-20=0
10x=20
x= 20/10
x=2
y=7-2x
y=7-2(2)
y=7-4
y=3
----------------------
|
|. x = 2
|
|. y =3
|---------------------
I hope you got the answer.
Don't forget to mark me the Brainliest !!
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