Question

solve the given pair of linear equation 2x+3y=6 x+y=8


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Answer 1

Answer:

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Step-by-step explanation:

2x + 3y = 6 .....(i)

x + y = 8......(ii)

multiplying equation (ii) with 2 and subtract both the equation

2x + 3y = 6

2x + 2y = 16

- - -

y = -10

now from equation (ii)

x+ (-10) =8

x -10 =8

x =8+10

x =18

hence x= 18 & y =-10

Answer 2

Answer:

x = 24 & y = -16

Step-by-step explanation:

From (ii) y=8-x

 now substitute y = 8- x in equ (i)

so we get :

 2x + 3(8-x) = 6

 2x + 24 - 3x

=> x = 24

substitute x= 24 in equ(ii)

we get y = -16

Hope this helps mate :)

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