Math, asked by TbiaSupreme, 1 year ago

Solve the given puzzle using the equation-Priyanshi has 5 chocolates less than Dhruv. If both have 15 chocolates, find the number of chocolates each has?

Answers

Answered by mysticd
0
Solution :

Let number of chocolates

Dhruv had = x

Number of Chocolates

Priyanshi had = x - 5

According to the problem given ,

Total chocolates = 15

=> x + x - 5 = 15 ----( 1 )

[ ( 1 ) Required linear equation ]

=> 2x - 5 = 15

=> 2x = 15 + 5

=> 2x = 20

=> x = 20/2

x = 10

Therefore ,

Number chocolates Dhruv had = x = 10

Number of chocolates Priyamshi had

= x - 5

= 10 - 5

= 5

••••••
Answered by siddhartharao77
0

Answer:

5,10

Step-by-step explanation:

Let the number of chocolates dhruv has = 'x'.

(i)

Given that Priyanshi has 5 chocolates less than Dhruv.

⇒ x - 5.

(ii)

Total number of chocolates = 15.

⇒ x + x - 5 = 15

⇒ 2x - 5 = 15

⇒ 2x = 20

⇒ x = 10.


Therefore:

Number of chocolates Dhruv has = 10.

Number of chocolates Priyanshi has = 5.


Hope this helps!

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