Solve the given puzzle using the equation-Priyanshi has 5 chocolates less than Dhruv. If both have 15 chocolates, find the number of chocolates each has?
Answers
Answered by
0
Solution :
Let number of chocolates
Dhruv had = x
Number of Chocolates
Priyanshi had = x - 5
According to the problem given ,
Total chocolates = 15
=> x + x - 5 = 15 ----( 1 )
[ ( 1 ) Required linear equation ]
=> 2x - 5 = 15
=> 2x = 15 + 5
=> 2x = 20
=> x = 20/2
x = 10
Therefore ,
Number chocolates Dhruv had = x = 10
Number of chocolates Priyamshi had
= x - 5
= 10 - 5
= 5
••••••
Let number of chocolates
Dhruv had = x
Number of Chocolates
Priyanshi had = x - 5
According to the problem given ,
Total chocolates = 15
=> x + x - 5 = 15 ----( 1 )
[ ( 1 ) Required linear equation ]
=> 2x - 5 = 15
=> 2x = 15 + 5
=> 2x = 20
=> x = 20/2
x = 10
Therefore ,
Number chocolates Dhruv had = x = 10
Number of chocolates Priyamshi had
= x - 5
= 10 - 5
= 5
••••••
Answered by
0
Answer:
5,10
Step-by-step explanation:
Let the number of chocolates dhruv has = 'x'.
(i)
Given that Priyanshi has 5 chocolates less than Dhruv.
⇒ x - 5.
(ii)
Total number of chocolates = 15.
⇒ x + x - 5 = 15
⇒ 2x - 5 = 15
⇒ 2x = 20
⇒ x = 10.
Therefore:
Number of chocolates Dhruv has = 10.
Number of chocolates Priyanshi has = 5.
Hope this helps!
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