Question

Solve the given puzzle using the equation-The weight of Rahul is 5 kg more than Sachin. The weight of Samir is 12 kg less than double the weight of Sachin. If the total weight of all the three is 93, find the weight of each one of them.

Answer 1

Let the weights of Rahul, Sachin and

Samir be x, y and z.

As per given data,

x = y + 5......(1)

z = 2y - 12.....(2)

x + y + z = 93.....(3)

Using (1) and (2) in (3)

(y+5) + y + (2y-12) = 93

4y -7 = 93

4y = 100

y = 25

(1) gives x = 25 +5 = 30

(2) gives z = 2(25) -12 = 38

Rahul's weight is 30 kg
Sachin's weight is 25 kg
Samir's weight is 38 kg

Answer 2

SOLUTION :

Let the weight of Sachin = x kg

Weight of Rahul = (x + 5 ) kg

Weight of Samir = (2x - 12) kg

GIVEN : Total weight of Sachin, Rahul and Samir = 93 kg

Total weight of Sachin, Rahul and Samir = x + (x + 5 ) + (2x - 12)

93 = x + (x + 5 ) + (2x - 12)

93 = 4x -7

93 + 7 = 4x

100 = 4x

x = 100/4

x = 25 kg

weight of Sachin = x kg= 25 kg

Weight of Rahul = (x + 5 ) kg = 25+5= 30 kg

Weight of Samir = (2x - 12) kg = 2×25 -12 = 50 - 12 = 38 kg

Hence, the weight of Sachin is 25 kg, weight of Rahul is 30 kg and the weight of Samir is 38 kg.

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