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Number is between 1 to 100
1st number divisible by 8 = 8
last number divisible by 8 = 96
Common difference = 8
Find the number of terms that are divisible by 8:
an = a1 + (n - 1)d
96 = 8 + 8(n - 1)
96 = 8 + 8n - 8
8n = 96
n = 96 ÷ 8 = 12
(i) Find the probability of that a number chosen is divisible by 8:
P(Divisible by 8) = 12/100 = 3/25
(ii) Find the probability of that a number chosen is NOT divisible by 8:
P(Not divisible by 8) = 1 - 3/25 = 22/25
Answer: (i) 3/25 (ii) 22/25
Answer:
Answer is 1) 3/25 and 2) 22/25
Step-by-step explanation:
In the given question,
First we have to find out the number between 1 to 100 which is divisible by 8,
The first number is 8
and the last number divisible by 8 = 96
Common difference = 8
To Find the number of term which is divisible by 8:
Use formula of A.P
an = a1 + (n - 1)d
96 = 8 + 8(n - 1)
or, 96 = 8 + 8n - 8
or 8n = 96
Therefore, n = 96 ÷ 8 = 12
(i) Probability of that a number divisible by 8:
P (Divisible by 8) = 12/100 = 3/25
(ii) Probability of number chosen is NOT divisible by 8:
P(Not divisible by 8) = 1 - 3/25 = 22/25
Hence the Answer is 3/25 and 22/25