Question

solve the given questions​

Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ that:\\\\i) \ a^2b(a-b^2)+ab^2(4ab-2a^2)-a^3b(1-2b)\\\\ii) \ 4st(s-t)-6s^2(t-t^2)-3t^2(2s^2-s)+2st(s-t)$

$\ Solution: \\\\i) \ a^2b(a-b^2)+ab^2(4ab-2a^2)-a^3b(1-2b)\\\\\rightarrow \ remove \ brackets \ and \ multiply \ value\\\\ \rightarrow a^3b-a^2b^3+4a^2b^3-2a^3b^2-a^3b+2a^3b^2\\\\\rightarrow -a^2b^3+4a^2b^3\\\\\rightarrow 3a^2b^3$

$ii) \ 4st(s-t)-6s^2(t-t^2)-3t^2(2s^2-s)+2st(s-t)\\\\\rightarrow \ 4s^2t-4st^2-6s^2t+6s^2t^2-6t^2s^2+3t^2s+2s^2t-2st^2\\\\\rightarrow \ 4s^2t-4st^2-6s^2t+3t^2s+2s^2t-2st^2\\\\\rightarrow \ -4st^2+3t^2s-2st^2\\\\\rightarrow \ -6st^2+3t^2s\\\\\rightarrow \ -3t^2s$

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Answer 2

Answer:

Refer to the attachment