solve the inequalities and represent the solution graphically on number line : 3x - 7 < 5 + x , 11 - 5x _< 1
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1 ) 3x - 7 < 5 + x
3x - x < 5 + 7
2x < 12
x < 12/2
x < 6
draw x = 6 line on a graph .
and shade the region x < 6 which is shown in
the graph red color.
2 ) 11 - 5x ≤ 1
- 5x ≤ 1 - 11
- 5x ≤ - 10
divide bothsides with - 5 , we get
( - 5x )/( - 5 ) ≥ ( - 10 )/( - 5 )
x ≥ 2
draw a line x = 2 , and shaded region which
shown in black lines .
I hope this helps you.
: )
3x - x < 5 + 7
2x < 12
x < 12/2
x < 6
draw x = 6 line on a graph .
and shade the region x < 6 which is shown in
the graph red color.
2 ) 11 - 5x ≤ 1
- 5x ≤ 1 - 11
- 5x ≤ - 10
divide bothsides with - 5 , we get
( - 5x )/( - 5 ) ≥ ( - 10 )/( - 5 )
x ≥ 2
draw a line x = 2 , and shaded region which
shown in black lines .
I hope this helps you.
: )
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Answered by
8
Given that,
3x – 7 > 5x – 1
Now by adding 7 to both the sides, we get
3x – 7 +7 > 5x – 1 + 7
3x > 5x + 6
Again by subtracting 5x from both the sides,
3x – 5x > 5x + 6 – 5x
-2x > 6
Dividing both sides by -2 to simplify we get
-2x/-2 < 6/-2
x < -3
∴ The solutions of the given inequality are defined by all the real numbers less than -3.
Hence the required solution set is (-∞, -3)
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