Solve the inequality 4x+x.x greater than 21
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4x+x2= 21
4x cube (3)=21
64xcube (3)=21
ans = yes 4x+x.x is greater than 31
4x cube (3)=21
64xcube (3)=21
ans = yes 4x+x.x is greater than 31
dipaxi:
im sorry not 31 its 21
Answered by
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4x+x^2>21
=> 4x+x^2-21>21-21
=> 4x+x^2-21>0
=> x^2+4x-21>0
=> x^2+7x-3x-21>0
=> x(X+7)-3(X+7)>0
=> (x-3)(x+7)>0
Therefore x-3>0
or,x-3+3>0+3
or,x >3
AND x+7>0
or,X+7-7>0-7
or x>-7
HOPE MY ANS HELPS YOU MATE!!
@Lazarus!!!
=> 4x+x^2-21>21-21
=> 4x+x^2-21>0
=> x^2+4x-21>0
=> x^2+7x-3x-21>0
=> x(X+7)-3(X+7)>0
=> (x-3)(x+7)>0
Therefore x-3>0
or,x-3+3>0+3
or,x >3
AND x+7>0
or,X+7-7>0-7
or x>-7
HOPE MY ANS HELPS YOU MATE!!
@Lazarus!!!
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