Math, asked by rehan1454, 3 months ago

Solve the inequation 3x +1≤ 16; x ∈ N

Answers

Answered by Anonymous
11

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 \sf3x + 1 \leqslant 16

 \sf3x =  16 - 1

 \sf \:x =  \frac{15}{3}  = 5

So x=5

Hope it helps you.....

Answered by marwaharushil
3

Answer:

1,2,3,4,5

Step-by-step explanation:

3x + 1 < 16

3x < 16 - 1

x < 15/3

x < 5

x = 1,2,3,4,5

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