Question

solve the last 2 missing numbers pls​

Answer 1

Step-by-step explanation:

2+3+6=7

3+4+12=13

4+5+20=21

5+6+30=31

6+7+42=43

Answer 2

Answer:

$6^2 + 7^2 + 42^2 = 43^2$

Missing numbers are 42 and 43.

Step-by-step explanation:

The pattern shows:

$1^2 + 2^2 + 2^2 = 3^2$

$1^2 + 2^2 + (1*2)^2 = (1*2 +1)^2$

$2^2 + 3^2 + (2*3)^2 = (2*3 +1)^2$

$3^2 + 4^2 + (3*4)^2 = (3*4 +1)^2$

$4^2 + 5^2 + (4*5)^2 = (4*5 +1)^2$

$5^2 + 6^2 + (5*6)^2 = (5*6 +1)^2$

$6^2 + 7^2 + (6*7)^2 = (6*7 +1)^2$

$6^2 + 7^2 + 42^2 = 43^2$