Question

solve the linear equation 0.3x+0.4y=2.5,0.5x-0.3y=0.3​

Answer 1

$\huge \bold \blue{heya}$

0.3x+0.4y=2.5-----(1)

0.5x0.3y=0.3-------(2)

Multiplying both the equations by 10,

3x+4y=25-----(3)

5x-3y=3-----(4)

Again Multiplying (3) by 5 and (4) by 3,

15x+20y=125------(5)

15x-9y=9------(6)

Subtracting (6) from (5),

29y=116

y=4

Substituting this value of y in (6),

15x-9(4)=9

15x-36+9

15x=45

x=3

Answers:

↪x=3

↪y=4

Answer 2

$0.3x + 0.4y = 2.5 \\ \frac{3x}{10} + \frac{4y}{10} = \frac{25}{10} \\ 3x + 4y = 25 ....1$

$0.5x - 0.3y = 0.3 \\ \frac{5x}{10} - \frac{3y}{10} = \frac{3}{10} \\ 5x - 3y = 3.....2$

Multiply 1 with 3

we get

$9x + 12y = 75.....3$

multiply 2 with 4

we get

$20x - 12y = 12.....4$

adding 3 and 4

we get

$x = 3$

put x=3 In 1

$y = 4$

Therefore x=3

y=3