Question

Solve the linear equation ​

Answer 1

Step-by-step explanation:

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Answer 2

GIVEN :-

$2 \dfrac{1}{3} - \dfrac{x - 2}{4} = \dfrac{x - 1}{6}$

TO FIND :-

The value of x

SOLUTION :-

We shall Tranpose - $\dfrac{x-2}{4}$ to RHS

$2 \dfrac{1}{3} = \dfrac{x - 1}{6} + \dfrac{x - 2}{4}$

Converting 2 1/3 into improper fraction

$2 \dfrac{1}{3} = \dfrac{3 \times 2 + 1}{3}$

$2 \dfrac{1}{3} = \dfrac{7}{3}$

$\dfrac{7}{3} = \dfrac{x - 1}{6} + \dfrac{x - 2}{4}$

LCM of RHS 6, 4 is 12

$\dfrac{7}{3} = \dfrac{(x - 1) \times 2 + (x - 2) \times 3}{12}$

$\dfrac{7}{3} = \dfrac{2x - 2 + 3x - 6}{12}$

$\dfrac{7}{3} = \dfrac{5x - 8}{12}$

$7 = \dfrac{5x - 8}{4}$

DO CROSS MULTIPLICATION

$7 \times 4 = 5x - 8$

$28 = 5x - 8$

Transpose -14 to LHS

$28 + 8 = 5x$

$36= 5x$

$x = \dfrac{36}{5}$