Solve the linear equation.
8y+32=2(25y−15)−11y8y+32=2(25y−15)−11y
Answers
Answered by
10
It seems like you put the same equation up there twice, but no worries! :)
8y + 32 = 2(25y - 15) - 11y
Simplify.
8y + 32 = 50y - 30 - 11y
Add like terms.
8y + 32 = (50y - 11y) - 30
Simplify.
8y + 32 = 39y - 30
Now we must subtract 32 from both sides.
8y = 39y - 30 - 32
Then, subtract 39y from both sides.
8y - 39y = -30 - 32
Simplify.
-31y = -62
Finally, divide both sides by -31.
Simplify.
y = 2
urbanlosa:
Yes thank you
Answered by
4
Answer:
Step-by-step explanation:
=>8y+32=2(25y-15)-11y (8y+32)=2 (25y-15y)-11y
=>8y+32=50y-30-88y-352y=2 (25y-15y)-11y
=>8y+32=-390y-30=2(25y-15y)-11y
=>398y+62=20y-11y
=>361y=-62
=>y=-62/361
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