Question

Solve the linear equation.
8y+32=2(25y−15)−11y8y+32=2(25y−15)−11y

Answer 1

It seems like you put the same equation up there twice, but no worries! :)

8y + 32 = 2(25y - 15) - 11y

Simplify.

8y + 32 = 50y - 30 - 11y

Add like terms.

8y + 32 = (50y - 11y) - 30

Simplify.

8y + 32 = 39y - 30

Now we must subtract 32 from both sides.

8y = 39y - 30 - 32

Then, subtract 39y from both sides.

8y - 39y = -30 - 32

Simplify.

-31y = -62

Finally, divide both sides by -31.

$\dfrac{\cancel{-31}\text{y}}{\cancel{-31}} = \dfrac{-62}{-31}$

Simplify.

y = 2

Answer 2

Answer:

$y = \frac{ - 62}{361}$

Step-by-step explanation:

=>8y+32=2(25y-15)-11y (8y+32)=2 (25y-15y)-11y

=>8y+32=50y-30-88y-352y=2 (25y-15y)-11y

=>8y+32=-390y-30=2(25y-15y)-11y

=>398y+62=20y-11y

=>361y=-62

=>y=-62/361

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