Solve the linear equation graphically 3x + 8y = 12 ; 3x +2y = -6 Also find the Cordinates of the vertices triangle formed by these linear and x- axis
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let take
3x + 8y -12 = 0 (I)
3x + 2y + 6 = 0 ll)
subtract equation Il from I
3x + 8y - 12
-3x - 2y - 6
= 6y - 18
6y = 18
y = 18 /6
y= 3
put y = 3 in equation I
3x + 8(3) - 12 = 0
3x + 24 - 12 = 0
3x + 12 = 0
3x = - 12
x = 12/-3
x= -4
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