solve the linear equation in two variables by substitution method root 3 x + root 2 y is equal to 6 and root 5 x + root 3 y is equal to 8 class 10th
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Answer:
Hi
Hi3x 2y = v3 -(1)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v2
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v225v2 15V5+ v3y = v2
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v225v2 15V5+ v3y = v2V3y = 2 - 25v2 +15V5
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v225v2 15V5+ v3y = v2V3y = 2 - 25v2 +15V5y=(15V5 24v2 /v3
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v225v2 15V5+ v3y = v2V3y = 2 - 25v2 +15V5y=(15V5 24v2 /v3y =[ 3(5v5-8 2) V( V3)
Hi3x 2y = v3 -(1)V5x+ 3y = v2--( 2)multiply equation ( 1) with v3 and equation(2) with v2, we get,3x- V6y3-(3)V10x + V6y = 2 -(4)add (3) and (4), we get3x + V10x = 5x(3t 10) = 5x = 5/(3+ V10)x = [ 5( V10 3)( V10 +3 X V10 3)]x= 5( 10-3y[(V10 - (3]x = 5( V10 -3 (10-9)x = 5V10 15putx value in equation (2), we get,V5 (5V10 - 15) + V3y= v225v2 15V5+ v3y = v2V3y = 2 - 25v2 +15V5y=(15V5 24v2 /v3y =[ 3(5v5-8 2) V( V3)y [ v3 x v3 (5V5-8v2 ( V3 )
x v3 (5V5-8v2 ( V3 )y [v3 (5/5 8v2) ]
x v3 (5V5-8v2 ( V3 )y [v3 (5/5 8v2) ]y 5V15- 8V6
I hope this helps you.