Question

Solve the linear equations by elimination method 3x+2y=1 and 2x-4y=2

Answer 1

$3x + 2y = 1....1 \\ 2x - 4y = 2....2$
multiply 1 with 2 we get
$6x + 4y = 2....3$
adding 2 and 3 we get
$8x = 4 \\ x = \frac{4}{8} \\ x = \frac{1}{2}$
substitute x= 1/2 in 1
$3 \times \frac{1}{2} + 2y = 1 \\ \frac{3}{2} + 2y = 1 \\ 3 + 4y = 2 \\ 4y = 2 - 3 \\ y = - \frac{1}{4}$
Hope this helps you:-))))
don't forget to do it brainleist.