solve the maths problem of IX std samacheer portions, If (x+a)(x+b)(x+c) ≡ x3 -10 x2 +45x-15 find a+b+c, 1/a + 1/b + 1/c and a2 + b2 + c2
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a+b+c= -10
a2+ b2 +c2 = 10
and 1/a +1/b +1/c = -3
a2+ b2 +c2 = 10
and 1/a +1/b +1/c = -3
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