Question

Solve the numerical in the attachment

Standard:- 10

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Answer 1

Hey mate!

Here's your answer!!
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✬ Resistance = 3 Ω

✬ Reading of ammeter = 2 A

✬ Potential difference = 18 V
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Kindly refer to the given attachment file above for the complete answer!
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$\boxed{Hope\:it\:helps\:you!}$
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Answer 2

$\textbf{Your answer is -}$

Let , R1 = R and R2 = 6ohm

Let, V1 = 6V and V2 = 12V


We know that in series combination current I is same in all resistance

Now, according to ohms law

l = V2/R2

=> I = 12/6

=> I = 2ampere

So, 2 ampere current flow through a conductor .


a) According to ohms law

V1 = lR1

=> R1 = V1/I

=> R = 6/2

=> R = 3 ohm


b) Current flow through through the conductor is 2 ampere . So , reading of voltmeter is 2ampere .


c) Total voltage is

V1 + V2 = 6 + 12 = 18Volt

So, potential difference across the terminal of the battery is 18 volt


$\textbf{【 Hope it helps you 】}$