Question

Solve the numerical ques 11 in the attachment

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Answer 1

Thanks for asking the question!

ANSWER::

(a) R₅ and R₄ are connected in series because the current passing is equal and in others there are joints which are making the current to split.

(b)R₂ and R₃ are connected in parallel because the current passing is not equal .

(c) Every resistor is of 2 ohm

R₂ and R₃ in parallel combination so , 1/R = 1/R₂ + 1/R₃

1/R = 1/2+1/2

R = 1 ohm

Now removing R₂ and R₃ and making it a single resistor(name it R₀) of 1 ohm . Now the current won't pass from R₁ as it is getting a path which has no resistor.

So , the resistor which are in series are R₅ , R₀ , R₄

Now , R₀ + R₄ + R₅ = 1 + 2 + 2 = 5 ohm (series combination)

Now the current ,

V = IR

V = I(5)

I = V/5 will be the current.

Hope it helps!