Question

solve the ordinary differential equation 3y +5y2=sinx, y(0)=5 by Euler theorem ,you need to
equation rewrite
(a) y'=3x
(b) y=4x+5
(c) y "=3
(d) none of these​

Answer 1

Step-by-step explanation:

Given Solve the ordinary differential equation 3y +5y2=sin x, y(0) = 5 by Euler theorem

• So the given ordinary differential equation is 3y + 5y^2 = sin x, y(0) = 5
• We need to solve the differential equation by Euler theorem.
• So we get  
•                3 x dy/dx + 5y^2 = sin x , y(0) = 5
•                3dy/dx + 5y^2 = sin x
•                3dy/dx = sin x – 5y^2
•             Or dy/dx = sin x – 5y^2 / 3
•           Or dy/dx = 1/3(sinx – 5y^2) , y(0) = 5

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