Solve the pair of equations by reducing them to a pair of linear equations.
6x + 3y = 6xy
2x + 4y = 5xy
Answers
Answered by
46
Hi,
6x + 3y = 6xy
divide each term with xy ,
=>6/y + 3/x = 6 ---( 1 )
2x + 4y = 5xy
divide each term with xy , we get
=> 2/y + 4/x = 5 ---( 2 )
Let 1/x = a , 1/y = b
6/y + 3/x = 6 => 6b + 3a = 6 ---( 3 )
2/y + 4/x = 5 => 2b + 4a = 5 ----( 4 )
Do [ ( 3 ) - 3 × ( 4 ) ], we get
6b + 3a = 6
6b + 12a = 15
_____________
- 9a = -9
a = ( -9 )/( -9 )
a = 1
Substitute a = 1 in equation ( 4 ),
we get
2b + 4 = 5
2b = 5 - 4
b = 1/2
Therefore ,
1/x = a = 1 =>x = 1 ,
1/y = b = 1/2 => y = 2
I hope this helps you.
: )
6x + 3y = 6xy
divide each term with xy ,
=>6/y + 3/x = 6 ---( 1 )
2x + 4y = 5xy
divide each term with xy , we get
=> 2/y + 4/x = 5 ---( 2 )
Let 1/x = a , 1/y = b
6/y + 3/x = 6 => 6b + 3a = 6 ---( 3 )
2/y + 4/x = 5 => 2b + 4a = 5 ----( 4 )
Do [ ( 3 ) - 3 × ( 4 ) ], we get
6b + 3a = 6
6b + 12a = 15
_____________
- 9a = -9
a = ( -9 )/( -9 )
a = 1
Substitute a = 1 in equation ( 4 ),
we get
2b + 4 = 5
2b = 5 - 4
b = 1/2
Therefore ,
1/x = a = 1 =>x = 1 ,
1/y = b = 1/2 => y = 2
I hope this helps you.
: )
Answered by
15
HELLO DEAR,
GIVEN:-
6x + 3y = 6xy
=> 2x + y = 2xy------------( 1 )
2x + 4y = 5xy-----------( 2 )
form---------( 1 ) & ---------( 2 )
2x + y = 2xy
2x + 4y = 5xy
---------------------
-3y = -3xy
x = 1 [ put in -----( 1 )]
we get,
2(1) + y = 2(1)y
2y - y = 2
y = 2 , x = 1
I HOPE ITS HELP YOU DEAR,
THANKS
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