Solve the pair of equations by reducing them to a pair of linear equations.
2/x + 3/y = 13
5/x - 4/y = -2 where x≠0, y≠0
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Hi ,
It is given that ,
2/x + 3/y = 13 -----( 1 )
5/x - 4/y = -2 ------( 2 )
Let 1/x = a , 1/y = b
2a + 3b = 13 ----( 3 )
5a - 4b = -2 ----( 4 )
Do [ 4 × ( 3 ) + 3 × ( 4 ) ]
8a + 12b = 52
15a - 12b = -6
____________
23a = 46
a = 46/23
a = 2
substitute a = 2 in equation ( 3 ), we get
5 × 2 - 4b = -2
-4b = -2 - 10
b = ( -12 )/( -4 )
b = 3
Therefore ,
1/x = a = 2/1 => x = 1/2
1/y = b = 3/1 => y = 1/3
I hope this helps you.
: )
It is given that ,
2/x + 3/y = 13 -----( 1 )
5/x - 4/y = -2 ------( 2 )
Let 1/x = a , 1/y = b
2a + 3b = 13 ----( 3 )
5a - 4b = -2 ----( 4 )
Do [ 4 × ( 3 ) + 3 × ( 4 ) ]
8a + 12b = 52
15a - 12b = -6
____________
23a = 46
a = 46/23
a = 2
substitute a = 2 in equation ( 3 ), we get
5 × 2 - 4b = -2
-4b = -2 - 10
b = ( -12 )/( -4 )
b = 3
Therefore ,
1/x = a = 2/1 => x = 1/2
1/y = b = 3/1 => y = 1/3
I hope this helps you.
: )
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