Solve the pair of linear equation 21x+47y=110. 47x+21y=162
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Answered by
45
We have
21x + 47y = 110 (1)
47x + 21y = 162 (2)
Adding Equations (1) and (2), we have
68x + 68y = 272
or x + y = 4 (5)
Subtracting Equation (1) from Equation (2), we have
26x – 26y = 52
or x – y = 2 (6)
On adding and subtracting Equations (5) and (6), we get
x = 3, y = 1
21x + 47y = 110 (1)
47x + 21y = 162 (2)
Adding Equations (1) and (2), we have
68x + 68y = 272
or x + y = 4 (5)
Subtracting Equation (1) from Equation (2), we have
26x – 26y = 52
or x – y = 2 (6)
On adding and subtracting Equations (5) and (6), we get
x = 3, y = 1
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Answered by
14
I hope it will help you
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